Inclined plane is moved towards right with an acceleration of 5m/s^2 as shown in fig. Find force in newton which block of mass 5kg exerts on the incline plane.(All surfaces are smooth)
Asked by m.nilu
25th July 2018,
8:33 AM
Answered by Expert
Answer:
As shown in figure, Block is subjeted to acceleration due to gravity and acceleration due to movement of inclined plane.
Acceleration vectors are resolved in parallel and perpendicular to surface of inclined plane in figure .
we have, N+m×a sin 37º = m×g cos37° .............(1)
where N is normal force, m is mass of block, a is acceleration of inclined plane and g is acceleration due to gravity.
By substituting the values, m=5 kg, a = 5 m/s2 , we get N = 24 N
Answered by Expert
25th July 2018,
10:47 AM
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