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Home / Doubts and Solutions/JEE/Physics

In the arrangement shown what should be the mass of block A so that the system remains at rest .Also find force exerted by string on the pulley Q.

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Asked by m.nilu 3rd August 2018, 10:12 AM
Answered by Expert
Answer:
As shown in figure, In equlibrium state, force balance condition for 2 kg block resting on inclined plane is given by
 
begin mathsize 12px style T subscript 1 plus space 2 g sin 30 space equals space T subscript 2 end style ...............(1)
but we have, T1 = 2×g and T2 = m×g  ................(2)
 
By substituting eqns.(2) in eqn(1) and solving for m, we get m = 3 kg
 
Force exerted by the string on pulley Q is T2 = 3×9.8 = 29.4 N

Answered by Expert 6th August 2018, 4:04 PM
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