In the arrangement shown in fig neglect the masses of the pulley and string and also friction.The accelerations of blocks A and B are
Asked by m.nilu
24th July 2018,
11:35 AM
Answered by Expert
Answer:
Free body diagrams for two mass blocks and two pulleys are given in figure.
Force balance equations for all the cases are given below
For m1 :- 
For m2 :- 
for pulley P1 :- 2×T - T = 0 × aP1 ......................... (3)
for pulley P2 :- T2 - 2×T = 0 × aP2 .....................(4)
By solving Eqns. (1), (2), (3) and (4) , we get a1 = - g and a2 = g
Hence both blocks are moving downwards with acceleration g m/s2
Answered by Expert
8th August 2018,
3:39 PM
Rate this answer
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
You have rated this answer /10
Your answer has been posted successfully!
RELATED STUDY RESOURCES :
Browse free questions and answers by Chapters
- 1 Thermodynamics
- 2 Gravitation
- 3 Electromagnetic Waves
- 4 Communication Systems
- 5 Laws of Motion
- 6 Current Electricity
- 7 Work, Energy and Power
- 8 Kinematics
- 9 Physics and Measurement
- 10 Rotational Motion
- 11 Properties of Solids and Liquids
- 12 Kinetic Theory of Gases
- 13 Oscillations and Waves
- 14 Electrostatics
- 15 Magnetic Effects of Current and Magnetism
- 16 Electromagnetic Induction and Alternating Currents
- 17 Optics
- 18 Dual Nature of Matter and Radiation
- 19 Atoms and Nuclei
- 20 Electronic Devices
Trending Tags
Latest Questions
JEE Main Mathematics
Asked by amaladelsingh
28th October 2020,
10:24 PM
CBSE X Biology
Asked by reenacharan2008
28th October 2020,
9:11 PM
