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Home / Doubts and Solutions/JEE/Physics

In the arrangement shown in fig all surfaces are smooth .Select the correct alternative (a)for any value of theta acceleration of A and B are equal (b) contact force bet the two blocks is zero only if mA/mB=tan theta (c)contact force bet the two blocks is zero for any value of ma it mB(d) normal reactions exerted by the wedge on the blocks are equal

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Asked by m.nilu 27th July 2018, 1:00 PM
Answered by Expert
Answer:
(a)for any value of theta acceleration of A and B are equal
This is true. Contact force between the blocks is zero because surfaces are smooth, there is no friction.
Since the contact force is zero, movement of blocks are separated. Each block moves with acceleration gsinθ. 
 
(b) contact force bet the two blocks is zero only if mA/mB=tan theta
This is false. Contact force between the blocks is zero because surfaces are smooth, there is no friction. 
 
(c) contact force bet the two blocks is zero for any value of ma it mB
This is false. reason is same as that of (b)
 
(d) normal reactions exerted by the wedge on the blocks are equal
This is false. Normal reaction depends on the mass of individual block. It appears masses of the blocks are not equal

Answered by Expert 1st August 2018, 2:36 PM
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