If the kinetic energy of a body is increased by 69%, then its momentum increased by ?
Asked by dipanshusingla029
3rd April 2018,
5:51 PM
Answered by Expert
Answer:
Kinetic energy K = (1/2)mV2
if we take log on both side, log(K) = log(m/2) + 2 log( V )
differentiate both side (δK/K) = 2×(δV/V); we are given (δK/K) = 0.69; hence (δV/V)=0.345;
since momentum directly proportional to velocity, momentum increases by 34.5%
Answered by Expert
3rd April 2018,
10:19 PM
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