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If the binding energy of the electron in hydrogen atom is 13.6 eV energy of the first excited state of Ally Li++ is

Asked by vaibhavdmhaske 20th October 2018, 4:05 PM
Answered by Expert
Answer:
Energy levels for hydrogen-like atom = begin mathsize 12px style negative fraction numerator 13.6 cross times Z squared over denominator n squared end fraction end style, where Z is atomic number and n is orbital quantum number.
lor Li++, Z = 3, n=2 for first excited state.
 
Hence Energy of first excited state of Li++ = -(13.6×9)/4 = -30.6 eV
Answered by Expert 21st October 2018, 4:54 AM
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