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If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is
(a)4piG/3gR               (b)3piR/4gG
(c)3g/4piRG               (d)piRg/12G

Asked by निकोदिमुस 4th December 2017, 6:44 PM
Answered by Expert
Answer:
If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is
(a)4piG/3gR               (b)3piR/4gG
(c)3g/4piRG               (d)piRg/12G
 
g equals fraction numerator G M over denominator R squared end fraction
space d e n s i t y space equals space fraction numerator m a s s over denominator v o l u m e end fraction


M a s s space equals space space d e n s i t y space x space v o l u m e

M equals space rho space x fraction numerator 4 πR cubed over denominator 3 R squared end fraction equals space space rho space x fraction numerator 4 πR over denominator 3 end fraction

P u t space v a l u e space o f space M space i n space g equals fraction numerator G M over denominator R squared end fraction

rho space equals space fraction numerator 3 g over denominator 4 πRG end fraction
Answered by Expert 5th December 2017, 2:22 PM
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