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Home / Doubts and Solutions/NEET/Physics

If gE and gM are the acceleration due to gravity on the surfaces of the earth and moon respectively and if Millikan's oil drop experiment could be performed on the two surfaces, one will find the ratio 

electronic charge on the moon/electronic charge on the earth 

to be?

 

 

Asked by nasir.mirza 13th June 2018, 6:34 PM
Answered by Expert
Answer:
From the theory of Millikan's oil drop method, we know that charge q is proportional to radius of oil drop.
Also, radius of oil drop inversely proportional to √g , wher g is acceleration due to gravity.
Hence measured charge q is inversely proportional to √g. 
 
If qM is the electronic charge measured on moon and qE is electronic charge measured on Earth, then
 
begin mathsize 12px style q subscript M over q subscript E space equals space square root of g subscript E over g subscript M end root end style
Answered by Expert 15th June 2018, 11:03 AM
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