I had asked the question day before in a population of 8000,80people can not recognize the taste of phenyl thio carb amide find out the number of homozygous tasters in a but the correct answer is 6480 how please explain me
Hi,
Given is,
Population – 8000 and Non-tasters – 80
Allele for ability to taste PTC is dominant ‘T’.
Hence, tasters will be of two genotypes – Homozyogous dominant (TT) and Heterozygous dominant (Tt).
Non-tasters will have one genotype = Homozygous recessive (tt).
Out of 8000, frequency of non-tasters (tt) = 0.01
frequency of homozygous tasters (TT) = 0.81
frequency of heterozygous tasters (Tt) = 0.18
0.01 of 8000 are non-tasters = 8000
0.81 of 8000 are homozygous tasters = 8000 x 0.81 = 6480
0.18 of 8000 are heterozygous tasters = 8000 x 0.18 = 1440
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