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Home / Doubts and Solutions/NEET/Physics

How to solve this?

Asked by Sharad 30th November 2017, 9:34 AM
Answered by Expert
Answer:
 
L e t space C A equals C 2 plus C 3 equals 2 plus 2 equals 4 space u f fraction numerator 1 over denominator C B end fraction equals fraction numerator 1 over denominator C 1 end fraction plus fraction numerator 1 over denominator C A end fraction equals 1 over 8 plus 1 fourth equals 3 over 8 space u f C B equals 8 over 3 u f fraction numerator 1 over denominator C D end fraction equals fraction numerator 1 over denominator C 5 end fraction plus fraction numerator 1 over denominator C 4 end fraction equals fraction numerator begin display style 1 x 2 end style over denominator begin display style 6 x 2 end style end fraction plus 1 over 12 equals 3 over 12 equals 1 fourth u f C D plus C 6 equals 4 plus 4 equals 8 space u f fraction numerator 1 over denominator C E end fraction equals fraction numerator 1 x 8 over denominator 1 x 8 end fraction plus 1 over 8 equals 9 over 8 space u f C E equals fraction numerator begin display style 8 end style over denominator 9 end fraction u f C B plus C E equals fraction numerator begin display style 8 end style over denominator 9 end fraction plus fraction numerator begin display style 8 x 3 end style over denominator begin display style 3 x 3 end style end fraction equals fraction numerator 8 plus 24 over denominator 9 end fraction equals 32 over 9 space u f space equals space C F fraction numerator 1 over denominator C e q end fraction equals fraction numerator 1 over denominator C F end fraction plus 1 over C 1 over 1 equals 9 over 32 plus 1 over C 1 over C equals 1 over 1 minus 9 over 32 equals 23 over 32 space u f C equals 32 divided by 23 space u f
Answered by Expert 7th December 2017, 3:10 PM
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