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How to find moment of inertia of equilateral triangle ?

Asked by rbhatt16 4th October 2017, 3:21 PM
Answered by Expert
Below are few steps which are helpful to find the moment of inertia of  an equilateral trriangle
with the system of particles about an axis passing through the center of mass of the system and perpendicular to the plane containing them.
- Let the measure of the side of the equilateral triangle be 'a'.
- The distance 'r' from any vertex of the equilateral triangle to the centre of mass can be found using the formula 
straight r equals fraction numerator square root of 3 over denominator 3 end fraction straight a
- The formula for moment of inertia is 
straight I equals begin inline style sum for straight i of end style straight m subscript space straight i space end subscript straight r subscript straight i superscript space 2 end superscript
- If there are 3 particles of mass 'm' placed at each of the vertex of this equilateral triangle then we consider three times m.
Answered by Expert 5th October 2017, 8:56 PM
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