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how should I determine whether to use 'theorem on equal ratios' or 'k-method' to solve problems on equal ratios? please give examples.

Asked by kishor.123 10th January 2015, 9:30 PM
Answered by Expert
Answer:
1 right parenthesis space K minus m e t h o d : a over b equals 2 over 3 rightwards double arrow a over 2 equals b over 3 equals k therefore a equals 2 k comma space b equals 3 k fraction numerator 2 a plus 3 b over denominator 2 a minus 5 b end fraction equals fraction numerator 2 left parenthesis 2 k right parenthesis plus 3 left parenthesis 3 k right parenthesis over denominator 2 left parenthesis 2 k right parenthesis minus 5 left parenthesis 3 k right parenthesis end fraction equals fraction numerator 4 k plus 9 k over denominator 4 k minus 15 k end fraction equals fraction numerator 13 k over denominator minus 11 k end fraction equals minus 13 over 11  2 right parenthesis space T h e o r e m space o n space e q u a l space r a t i o s : I f space fraction numerator a over denominator x plus y end fraction equals fraction numerator b over denominator y plus z end fraction equals fraction numerator c over denominator z minus x end fraction space t h e n space s h o w space t h a t space b equals a plus c fraction numerator b over denominator y plus z end fraction equals fraction numerator a over denominator x plus y end fraction equals fraction numerator c over denominator z minus x end fraction U sin g space t h o e r e m space o n space e q u a l space r a t i o s : fraction numerator b over denominator y plus z end fraction equals fraction numerator a plus c over denominator y plus z end fraction rightwards double arrow b equals a plus c
Answered by Expert 12th January 2015, 10:15 AM
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