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Home / Doubts and Solutions/JEE/Physics

  1. Find the value of n square from fig where n is refractive index

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Asked by venkat 28th February 2018, 11:50 PM
Answered by Expert
Answer:
as per law of refraction, 

begin mathsize 12px style fraction numerator sin space 45 over denominator sin space r end fraction space equals space mu space semicolon space space space space space space space sin space r space equals space fraction numerator 1 over denominator square root of 2 begin display style space end style begin display style mu end style end fraction space space space space space space semicolon space cos squared r space equals space 1 space minus space fraction numerator 1 over denominator 2 mu squared end fraction space................ left parenthesis 1 right parenthesis end style
 
 
as can be seen from figure, at left side boundary, the light ray incident at an angle (90-r);
begin mathsize 12px style f o r space t o t a l space i n t e r n a l space r e f l e c t i o n comma space sin left parenthesis 90 minus r right parenthesis space greater than space 1 over mu cos space r space greater than space 1 over mu space semicolon space cos squared space r space space greater than space 1 over mu squared............. left parenthesis 2 right parenthesis f r o m space left parenthesis 1 right parenthesis space a n d space left parenthesis 2 right parenthesis space space space open parentheses 1 space minus space fraction numerator 1 over denominator 2 mu squared end fraction close parentheses space greater than space 1 over mu squared semicolon b y space s o l v i n g space t h e space i n e q u a l i t y comma space w e space g e t space mu squared space greater than space 3 over 2 end style
 

Answered by Expert 1st March 2018, 10:19 AM
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