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Find the potential of the field created by the dipole at point A, located at a distance  r=0.5 m, in a direction at an angle 300,   relative to the electric moment of the dipole. Medium is water. The dipole is formed by charges q=2·10-7 C, that   located at a distance l=0.5 cm.
 

Asked by Zithinmuppalla 10th March 2021, 3:09 PM
Answered by Expert
Answer:
Potential of dipole is given as
 
begin mathsize 14px style V space equals space fraction numerator p space cos theta over denominator 4 pi epsilon subscript r space epsilon subscript o space r squared end fraction space end style
 
where p is electric dipole moment, θ is angle made by line joining dipole to the point where potential is required
with direction of dipole moment, εr is dielectric constant , εo is the permeability of free space and r is the distance
between dipole and the point where potential is required.
 
electric dipole moment  p = ( q d ) = 2 × 10-7 × 0.5 × 10-2 = 10-9 C m
 
dielectric constant of water εr = 80.4
 
Coulomb constant = 1/ ( 4πεo ) = 9 × 109 N m2 C-2 
 
V =  ( 9 × 109 × 10-9 × cos300 ) / ( 80.4 × 0.5 × 0.5 ) = 0.224 Volt
Answered by Expert 10th March 2021, 5:07 PM
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