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Evaluate : (cos3x-2cos4x)/(sin3x+2sin4x)

Asked by shreyasrivastavaprayag 13th August 2020, 11:06 PM
Answered by Expert
Answer:
To evaluate: (cos3x-2cos4x)/(sin3x+2sin4x)
(cos3x-2cos4x)/(sin3x+2sin4x) = cos3x sin3x - 2cos4x sin3x + 2sin4x cos3x - 4sin4x cos4x
equals fraction numerator sin 6 x over denominator 2 end fraction plus 2 open parentheses sin 4 x space cos 3 x space minus space cos 4 x space sin 3 x close parentheses minus 2 sin 8 x space space.... space left parenthesis S i n c e space 2 sin theta space cos theta equals sin 2 theta right parenthesis
equals fraction numerator sin 6 x over denominator 2 end fraction plus 2 sin open parentheses 4 x minus 3 x close parentheses minus 2 sin 8 x space space.
equals fraction numerator sin 6 x over denominator 2 end fraction plus 2 sin x minus 2 sin 8 x
equals fraction numerator sin 6 x over denominator 2 end fraction plus 2 open parentheses sin x minus sin 8 x close parentheses
Answered by Expert 14th August 2020, 11:12 AM
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