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Asked by hrittik12d
27th October 2018,
12:26 PM
Answered by Expert
Answer:
In the compound II, Chlorine atom is present at the adjacent carbon atom which exerts -I effect which increases the stability of Carboxylate ion and result in an increase in the acidity of acid.
In compound III, the chlorine atom is present near to the carboxylate ion which also exerts some amount of -I effect which makes it acidic but because of more distance between carboxylate ion and chlorine this effect is lesser than compound II.
In case of compound IV, the chlorine atom is present near to the carboxylate ion which also exerts some amount of -I effect which makes it acidic but because of more distance between carboxylate ion and chlorine this effect is lesser than compound II and III.
In the case of compound I, there is no such chlorine atom is present hence there is no any additional stabilization by -I effect. Hence carboxylate ion of this acid is less stable which makes it least acidic than other compounds.
Answered by Expert
29th October 2018,
1:28 PM
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