Calculate the wave number for the second line and limiting line of hydrogen atom if the first line appears at 456 nm in the calmer series
Asked by bhavya.vashisth8
19th August 2018,
7:16 PM
Answered by Expert
Answer:
The wave number for the second line and limiting line of H- atom of Balmer series is:
For Balmer series;
The wave number for the second line of H- atom of Balmer series is 20564.43 cm-1 and for limiting line is 27419 cm-1.
Answered by Expert
21st August 2018,
1:33 PM
Rate this answer
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
You have rated this answer /10
Your answer has been posted successfully!
RELATED STUDY RESOURCES :
Browse free questions and answers by Chapters
- 1 Classification of Elements and Periodicity in Properties
- 2 Chemical Bonding and Molecular Structure
- 3 States of Matter
- 4 Equilibrium
- 5 Hydrogen
- 6 Hydrocarbons
- 7 Environmental Chemistry
- 8 Solutions
- 9 Chemical Kinetics
- 10 Surface Chemistry
- 11 Biomolecules
- 12 Polymers
- 13 Chemistry in Everyday Life
- 14 Atomic Structure
- 15 Chemical Thermodynamics
- 16 Redox Reactions and Electrochemistry
- 17 p-Block Elements
- 18 d - and f - Block Elements
- 19 Some Basic Principles of Organic Chemistry
- 20 Organic Compounds Containing Halogens
- 21 Organic Compounds Containing Oxygen
- 22 Organic Compounds Containing Nitrogen
- 23 Co-ordination Compounds
- 24 Purification and Characterisation of Organic Compounds
- 25 s-Block Element (Alkali and Alkaline Earth Metals)
- 26 Solid State
- 27 Some Basic Concepts in Chemistry
- 28 General Principles and Processes of Isolation of Metals
- 29 Principles Related to Practical Chemistry
Trending Tags
Latest Questions
JEE Main Mathematics
Asked by amaladelsingh
28th October 2020,
10:24 PM
CBSE X Biology
Asked by reenacharan2008
28th October 2020,
9:11 PM
