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Assuming the length of a chain to be L and coefficient of static friction. Compute the maximum length of the chain which can be held outside without sliding?(2)If the coefficient of friction between an I sect and bowl isu and the radius of the bowl is r find the maximum height to which the insect can crawl in the bowl? A body of mass m is released from the top of s rough included plane . If the frictional force F, then body will reach the bottom with a velocity?


 

Asked by kanakpandeyyy 20th August 2018, 7:55 PM
Answered by Expert
Answer:
As informed earlier too many questions were asked in one posting.
Only one question is allowed per posting.
Hence only Second question is answered.
Figure shows the various forces acting on insect while it is crawling and when it is at the height h from bottom of the bowl.
 
The force that is pulling the insect down is mgsinθ. The insect is able to crawl up due to friction force f = μN = μ×mg×cosθ.
 
At the point,  where the insect starts falling, we have,    m×g×sinθ = μ×mg×cosθ  or tanθ = μ
 
from figure, it can be seen that,  tanθ begin mathsize 12px style equals space fraction numerator square root of r squared minus open parentheses r minus h close parentheses squared end root over denominator open parentheses r minus h close parentheses end fraction space equals space fraction numerator square root of 2 r h plus h squared end root over denominator open parentheses r minus h close parentheses end fraction space end style
hence the maximum height h has to satisfy the condition, begin mathsize 12px style fraction numerator square root of 2 r h plus h squared end root over denominator open parentheses r minus h close parentheses end fraction space equals space mu end style.................(1)
it is left to the user as an exercise to get h from eqn.(1), and h is given by
 
begin mathsize 12px style h space equals space fraction numerator square root of 1 plus 3 mu squared end root minus space open parentheses 1 plus mu squared close parentheses over denominator space open parentheses 1 space minus space mu squared close parentheses end fraction cross times r end style
Answered by Expert 21st August 2018, 6:41 PM
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