Contact

For Study plan details

10:00 AM to 7:00 PM IST all days.

Franchisee/Partner Enquiry (North)

Franchisee/Partner Enquiry (South)

Franchisee/Partner Enquiry (West & East)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

8788563422

Mon to Sat - 10 AM to 7 PM

# An object is projected from earth's surface with escape velocity at 30°with horizontal . What is the angle made by velocity with horizontal when object reaches height 2R from earth's surface?

Asked by jainkiran2014 6th January 2018, 9:54 AM
This problem can be solved by using the following conservation of energy relation in gravitational field.

m - mass of particle, M - mass of earth, v - velocity of particle, G - gravitational constant and r is position of particle from center of earth.

Initially object is projected at earth's surface with escape velocity.  It is required to get the velocity at a height of 2R (R is earth's radius) above earths surface.  Let us equate the total energy at both the positions as follows.

Let α be the angle that velocity vf makes with horizontal. It should be noted here initially the object is projected at an angle 30º at earths surface and the horizontal component of this velocity is unaffected.
then we can write the component form of the velocity as given below
Answered by Expert 7th January 2018, 7:55 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10

Tags: gravitation