an electron of mass 9*10^-31 kg moves around a nucleus in a circular orbit of radius 2 A° under the action of centripetal force 3.2N. then find the equivalent electric current is
Asked by likithparuchuri666
27th August 2018,
12:53 PM
Answered by Expert
Answer:
current density = n×e×v , where n is number density of electrons, e is charge on electron and v is its speed.
here we have to consider n =1.
centri-petal force = m×(v2/r) = 3.2 N ..............(1)
where m is mass of electron that is 9×10-31 kg and r is orbit radius which is given as 2 Aº
Hence v is calculated from (1), by substituting values for m and r. we get v = (8/3)×1010 m/s
hence current density = 1.6×10-19×(8/3)×1010 = 4.27 nA/m2
Answered by Expert
28th August 2018,
12:29 PM
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