an athlete of mass 87.4 kg jumps off the ground. the peak of his jump is 2.2m given that the athlete is completely stationary at the peak what was his take off velocity
Asked by saimassive007
7th July 2019,
10:29 PM
Answered by Expert
Answer:
At peak of his jump, athelet's total energy is potential energy = m×g×h ..................(1)
When he kicks off from the ground total energy is kinetic energy = (1/2)×m×v2 .............(2)
where m is mass of athelet, h is height he jumped , v is the take off velocity at staring time
and g is acceleration due to gravity
By conservation of energy, we have, m×g×h = (1/2)×m×v2 .................(3)
Hence from (3), 
Answered by Expert
8th July 2019,
9:58 AM
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