Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

A square loop of side 'a' is placed in the same plane as a long straight wire carrying a current i . The nearer side of loop is at a distance 'a' from the wire . The loop is moved away from the wire with a constant velocity v . The induced emf in the loop is

Asked by Deepak 31st August 2018, 9:53 PM
Answered by Expert
Answer:
 
induced emf e = -dφ/dt , where φ = B×A , B is magnetic field flux density, A is area of loop
 
magnetic field flux density at a point s, as shown in figure, B = begin mathsize 12px style fraction numerator mu subscript 0 space i over denominator 2 space pi space s end fraction end style, where i is the current flowing in the wire
induced emf, e  begin mathsize 12px style equals space minus space fraction numerator d ϕ over denominator d t end fraction space equals space minus space fraction numerator d over denominator d t end fraction open parentheses B cross times A close parentheses space equals space minus A fraction numerator d over denominator d t end fraction B space equals space minus A fraction numerator d B over denominator d s end fraction cross times fraction numerator d s over denominator d t end fraction space equals space a squared fraction numerator mu subscript o i over denominator 2 space pi space s squared end fraction v space space space V o l t end style
Answered by Expert 1st September 2018, 12:51 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Tags: induced-emf
Your answer has been posted successfully!

Chat with us on WhatsApp