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A satellite is in a circular orbit very close to the surface of the planet. At some point it is given an impulse in its direction of motion, causing its velocity to increase 'n' times. It now goes into an elliptical orbit, with the planet at the centre of the ellipse. The maximum possible value of 'n' for this to occur is 

(a) 2

(b) root of 2

(c) root of 2 + 1

(d) 1/ root of 2 -1

Asked by nasir.mirza 13th June 2018, 7:50 PM
Answered by Expert
Answer:
Let the satellite of mass m orbiting around a planet of mass M in a circular orbit of radius r.
 
Centripetal force is provided by Gravitational attractive force. 
 
hence begin mathsize 12px style G space fraction numerator M space m over denominator r squared end fraction space equals space m omega squared r space.................... left parenthesis 1 right parenthesis end style
where ω is angular speed that is related to linear speed v as v = ωr.

Potential Eneregy of the satellite begin mathsize 12px style U space equals space minus G fraction numerator M space m over denominator r end fraction.......................... left parenthesis 2 right parenthesis end style
Kinetic energy of Satellite, begin mathsize 12px style K space equals space 1 half m v squared space equals space 1 half m omega squared r squared space space equals space 1 half G fraction numerator M space m over denominator r end fraction space........................ left parenthesis 3 right parenthesis end style
In eqn.(3), mω2r is substituted as given in eqn(1).
 
if we compare eqn(2) and (3),  Kinetie energy is half of potential energy.
Also total energy is negative in order to bind the satellite to the planet in gravitational field. 
 
If the total energy is -ve, satellite will orbit in elliptical orbit. By giving more kinetic energy the orbit is changed.
 
If the kinetic energy is doubled, then total energy will be zero and the orbit will not be elliptic but it becomes parabola.
 
hence twice the kinetic energy is the maximum limit to keep the satellite in elliptical orbit around the planet.
 
Kinetic energy is proportional to square of speed. 
 
Hence to double the kinetic energy, speed should be increased to √2 times the initial value
Answered by Expert 15th June 2018, 10:36 AM
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