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A particle of mass m moves along the line y=x, with speed v. The magnitude of angular momentum about the point (square root of 2a,0) is

1) square root of 2
mva                                                               2) 2mva

3) mva                                                                     4) mva/ square root of 2

Asked by reachrahul123 14th October 2018, 9:35 PM
Answered by Expert
Answer:
As shown in figure, let the body of mass m moves along the line y=x with velocity v. Let its position at given instant is C as shown in figure.
 
Angular momentum about the point A (√2a, 0) is given by begin mathsize 12px style bold r with bold rightwards arrow on top bold cross times bold p with bold rightwards arrow on top space equals space open vertical bar r close vertical bar open vertical bar p close vertical bar sin theta space equals space a cross times space m v end style
where θ is the angle between vectors  begin mathsize 12px style r with rightwards arrow on top space a n d space p with rightwards arrow on top end style and |r|sinθ is the perpendicular distance between point A to the line y= x which is equal to a (refer figure)
Answered by Expert 15th October 2018, 3:00 AM
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