A particle of mass 4m which is at rest explodes into masses m,m,2m.Two of the fragments of masses m and 2m are found to move with equal speeds v each in opposite directions .The total mechanical energy released in the process of explosion is
Asked by m.nilu
17th September 2018,
8:38 PM
Answered by Expert
Answer:
Particle of mass 4m is at rest before explosion. Hence initial momentum is zero.
fragments m and 2m moves with speed v in opposite direction. Let V be the velocity of another mass m.
by conservation of momentum, m×v - 2m×v + m×V = 0 or V = v
Total kinetic energy = (1/2)×m×v2 + (1/2)×(2m)×v2 + (1/2)×m×v2 = 2×m×v2
Answered by Expert
18th September 2018,
2:11 PM
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