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Home / Doubts and Solutions/NEET/Physics

A man can swim directly a stream of width 100m in 4 minutes, when there in no current of water and in 5minutes when there is current of water. The velocity of the current of water in that stream is

Asked by valavanvino1011 31st August 2018, 7:00 AM
Answered by Expert
Answer:
Velocity of the man in still water (Vman) = 
begin mathsize 12px style fraction numerator 100 over denominator 4 cross times 60 end fraction equals space 5 over 12 space straight m divided by straight s end style
Velocity of the same man in water with a current (Vmcurrent) =
begin mathsize 12px style fraction numerator 100 over denominator 5 space cross times space 60 end fraction equals 1 third straight m divided by straight s end style
 
Let the velocity of the current be 'v'
Applying the concept of relative velocity, we get
Relative velocity of man with respect to the current as

begin mathsize 12px style square root of open square brackets straight v squared plus open parentheses 5 over 12 close parentheses squared close square brackets end root end style
But the velocity of this man with respect to the current is calculated as 1/3 m/s
So we get the equation

begin mathsize 12px style square root of open square brackets straight v squared plus open parentheses 5 over 12 close parentheses squared close square brackets end root equals open parentheses 1 third close parentheses end style
On solving this equation we get v = 1/4 m/s
Answered by Expert 31st August 2018, 12:48 PM
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