Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

93219 24448 / 89292 63204

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

81783 72169
OR

Chat with us on WhatsApp

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

Home / Doubts and Solutions/JEE/Physics

A force F=20N is applied to a block at rest as shown.After the block has moved a distance of 8m to the right, the direction of horizontal component of the force F is reversed.Find distance travelled before block stops after the F is reversed.

qsnImg
Asked by m.nilu 14th August 2018, 10:17 PM
Answered by Expert
Answer:
Figure shows the forces acting on 2 kg block.
 
In vertical direction, we have,  N + F sin37 = 2g .........(1)
where N is normal reaction force, we get N = 2g- Fsin37 = 2×9.8 - 20×.6 = 7.6 Newton
 
hence in horizontal direction, we have, F×cos37 - μ×N = m×a .........(2)
where μ is the coefficent of friction and a is acceleration 
 
we substitute values in eqn.(2) and get a = 7.05 m/s2
 
Starting from rest, if the block moves 8 m with acceleration a, then speed v of block after travelling 8 m is given by ,
 
v = begin mathsize 12px style square root of 2 cross times a cross times S end root space equals square root of 2 cross times 7.05 cross times 8 end root space equals space 10.62 space m divided by s end style
after moving 8m distance, if the horizontal component reversed, the applied force gives retardation to the movement of block.
 
when the horizontal component is reversed but still the block is moving implies that
frictional force and applied force both are in same direction. hence retardation ar is given by
 
F×cos37 + μ×N = m×ar  .....................(3)
Hence ar = 8.95 m/s2  
 
Distance travelled before stopping :- S = u2 / (2ar ) = (10.62×10.62)/(2×8.95) = 6.3 m
 
Answered by Expert 18th August 2018, 5:19 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Report an issue
Tags: distance
Previous Question
Next Question
Your answer has been posted successfully!

Free related questions

Find the total distance travelled in minimum time taken by car that starts from rest and comes to rest after achieying a peak velocity of 16m/s while moving along a straight line.The magnitude of maximum acceleration and maximum retardation is same at 2m/s^(2).
27th December 2021, 2:49 PM
A vehicle has the speed of 40 km/h. What does this mean?
4th February 2022, 9:26 AM
a car is moving with the acceleration 2m/s from rest find the distance traveled by the car in 10th second
17th April 2022, 9:33 PM
A car moves from Point A to Point B and comes back to Point A. Find distance and displacement.
26th May 2022, 2:24 PM
What is the difference between distance and displacement?
31st May 2022, 12:35 PM
RELATED STUDY RESOURCES :
JEE QUESTION ANSWERS

Browse free questions and answers by Chapters

Trending Tags

trigonometric equations Mole concept linear equations trigonometric ratios circle functions quadratic equation matrix operations equivalent resistance magnetic field

Latest Questions

CBSE X Biology
What is enzyme  
Asked by Sureshgowdayd548 28th October 2020, 10:50 PM
JEE Main Mathematics
The following pseudocode is executed using the “Paragraph words” dataset. At the end of the execution, CountB captures the number of verbs with letter count less than the average letter count of verbs. But the pseudocode may have mistakes in one or more lines. Identify all such lines (if any). It is a Multiple Select Question (MSQ).  Error in Line 4  Error in Line 8  Error in Line 11  Error at Line 12  Error in Line 17  Error at Line 18  Error in Line 21 The following pseudocode is executed using the “Words” table. What will be the value of A at the end of the execution?
Asked by amaladelsingh 28th October 2020, 10:24 PM
CBSE X Biology
I want a brief clarity on Taxonomy
Asked by reenacharan2008 28th October 2020, 9:11 PM

Chat with us on WhatsApp