A cube of edge length 'a' and density 'd' floats in a liquid of density 'D'. The maximum extra mass it can support without submerging is. ?
Asked by dipanshusingla029
24th March 2018,
1:19 PM
Answered by Expert
Answer:
Mass of Cube = Mass of displaced Liquid
a3 × d = a2 × x × D; i.e., x = a × (d/D)
The flloating body can be immersed further upto a depth of (a-x).
Mass of displaced liquid due to immersion of depth of (a-x) = a2 × (a-x) × D
Hence the required maximum extra mass = a2 × (a-x) × D
By substituting x from (1), we get the extra mass a3 × (D-d)
Answered by Expert
25th March 2018,
7:32 AM
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