A bomb is dropped from an aeroplane flying horizontally with a velocity of
720 KMPH at altitude of 980 m.Time taken by the bomb to hit the ground
Asked by valavanvino1011
10th August 2018,
6:16 AM
Answered by Expert
Answer:
The bomb starts with vertical component of speed zero.
hence time to hit the ground is calculated using the equation, h = (1/2)g×t2
980 = (1/2)×9.8×t2 ...........(1)
from eqn.1), we get t = 10√2 = 14.14 s
Answered by Expert
10th August 2018,
11:15 AM
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