A body of mass M moves in outer space with velocity v.It is desired to break the body into two parts so that the mass of one part is one tenth of the total mass .After the explosion ,the heavier part comes to rest while the lighter part continues to move in the original direction of motion.The velocity of the small part will be
Asked by m.nilu
28th September 2018,
8:52 PM
Answered by Expert
Answer:
Let V be the velocity of one-tenth of original mass after explosion.
due to momentum conservation, M×v = (9M/10)×0 + (M/10)×V
then V = 10×v
Answered by Expert
29th September 2018,
2:16 PM
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