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Home / Doubts and Solutions/NEET/Physics

A body of mass  2 kg initially  at  rest  is moved by a horizontal  force  of 0.5 N  on  a smooth  table . The  work  done by  the  force in  8 second 

Asked by parveenhooda2341 18th July 2018, 9:18 AM
Answered by Expert
Answer:
Workdone = Force×distance
 
Acceleration produced on 2 kg mass by .5 N force is = .5/2 = 0.25 m/s2 
 
distance moved in 8 sec starting from rest = (1/2)×a×t2  = (1/2)×0.25×64 = 8 m
 
workdone = 0.5×8 = 4 Joules

Answered by Expert 18th July 2018, 12:25 PM
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