A body is projected horizontally with a vertical of 4ms-1 from the top of a high tower .The velocity of the body after 0.7s is nearly:g=10ms-2
Asked by valavanvino1011
10th August 2018,
6:14 AM
Answered by Expert
Answer:
Horizontal componenet ux of velocity is unaffected.
At starting point, vertical component of velocity is zero.
After 0.7 s vertical component of velocity uy is given by, uy = g×t = 10×0.7 = 7 m/s
velocity of the body after 0.7s = 
Answered by Expert
10th August 2018,
12:00 PM
Rate this answer
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
You have rated this answer /10
Your answer has been posted successfully!
RELATED STUDY RESOURCES :
Browse free questions and answers by Chapters
- 1 Thermodynamics
- 2 Gravitation
- 3 Electromagnetic Waves
- 4 Communication Systems
- 5 Laws of Motion
- 6 Current Electricity
- 7 Work, Energy and Power
- 8 Kinematics
- 9 Physics and Measurement
- 10 Rotational Motion
- 11 Properties of Solids and Liquids
- 12 Kinetic Theory of Gases
- 13 Oscillations and Waves
- 14 Electrostatics
- 15 Magnetic Effects of Current and Magnetism
- 16 Electromagnetic Induction and Alternating Currents
- 17 Optics
- 18 Dual Nature of Matter and Radiation
- 19 Atoms and Nuclei
- 20 Electronic Devices
Trending Tags
Latest Questions
JEE Main Mathematics
Asked by amaladelsingh
28th October 2020,
10:24 PM
CBSE X Biology
Asked by reenacharan2008
28th October 2020,
9:11 PM
