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Home / Doubts and Solutions/JEE/Physics

A body is dropped from a building of height 1500 m. After two seconds another body is dropped from the same point. How long after the first body falls will the two bodies be 120 m apart

 

Asked by abhijithroshan24 8th September 2018, 9:24 PM
Answered by Expert
Answer:
At t=0, first body is dropped.
 
At t=2 s, speed u attained by first body, u = g×t = 9.8×2 = 19.6 m/s
               distance travelled by first body, S = (1/2)×g×t2 = (1/2)×9.8×2×2 = 19.6 m
 
               Now second body also dropped at this instant t = 2 s.
 
In order to find the time T after the instant t=2 s, so that the distance between them is 120 m,
we need to subtract the initial separation distance 19.6 m from the required final separation distance 120 m.
 
After time T from the instant t=2 s, distance travelled by first body,  S1 = 19.6×T + (1/2)×9.8×T2 ............(1)
After time T from the instant t=2 s, distance travelled by second body, S2 = (1/2)×9.8×T2 .......................(2)
 
we have, S1-S2 = 120-19.6 = 100.4 m .........................(3)
 
from (1), (2) and (3), we have 19.6×T = 100.4  or  T ≈ 5 s
 
Hence, 7 seconds after first body falls, two bodies will be 120 m apart
Answered by Expert 9th September 2018, 10:59 AM
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