a body covers a distance of 4m in 3rd and 12m in 5th sec if the motion is uniformely accelerated how far will it travels in the next 3sec
Asked by gargpuneet989
17th July 2018,
5:12 PM
Answered by Expert
Answer:
Let u0 be initial velocity and a be the uniform acceleration.
Velocity attained before 3rd second travel = u0 + 2a ;
distance travelled at 3rd second = u0 + 2a +(1/2)×a = u0 + 2.5×a = 4 ................(1)
Velocity attained before 5th second travel = u0 + 4a ;
distance travelled at 5th second = u0 + 4a +(1/2)×a = u0 + 4.5×a = 12 ................(2)
solving eqn.(1) and (2), we get u0 = -6 m/s , a = 4 m/s2
next 3 second means I assume the travelof 6th to 8th second
velocity atained before 6th sec travel = u0 + 5a = -6 + 5×4 = 14 m/s
distance travelled in 6th to 8th second = 14×3 + (1/2)×4×9 = 60 m
Answered by Expert
17th July 2018,
8:12 PM
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