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A block A of mass m is placed over a plank B of mass 2m.Plank B is placed over a smooth horizontal surface.The coefficient of friction bet A and B is 0.5.Block A is given a velocity v0 towards right.Acceleration of B relative to A is

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Asked by m.nilu 30th July 2018, 12:27 PM
Answered by Expert
Answer:
When block-A moves on block-B with velocity v0 , friction force μ×m×g is acting on Block-A in opposite direction of v0 .
As per newton's third law, equal and opposite reaction force is acting on block-B.
 
hence acceleration of block B begin mathsize 12px style equals space fraction numerator mu cross times m cross times g over denominator 2 cross times m end fraction space equals space fraction numerator 0.5 cross times 9.8 over denominator 2 end fraction space equals space 2.45 space m divided by s squared end style
Answered by Expert 31st July 2018, 2:19 PM
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Tags: acceleration
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