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A beam of monochromatic light is incident at i = 50° on one face of an equilateral prism, the angle of emergence is 40°, then the angle of minimum deviation is : |
Asked by Atulcaald
29th April 2018,
1:22 AM
Answered by Expert
Answer:
The angle of deviation is given by,
i+e = A-δ
where, i- angle of incidence
e- angle of emergence
A- angle of prism
δ- angle of deviation
For angle of minimum deviation δm,
i=e
Thus,
2i=A-δm
A= 60º ... (angle of equilateral prism)
→ 2(50º) = 60º - δm
→ 100º - 60º= δm
→δm= 40º
Thus the angle of minimum deviation is 40º
Answered by Expert
30th April 2018,
9:42 AM
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