a ball of mass 2kg moving with velocity 3m/s collides with another ball of mass 3 kg at rest. if two balls stick together after collision, then loss of kinetic energy of the system is
Asked by shrivithiyam7
6th April 2018,
11:37 PM
Answered by Expert
Answer:
total initial momentum = m1×v1 + m2×v2 = 2×3+3×0 = 6 kgm/s
momentum conserved, hence final momentum 6 = (m1+m2)×v; v = 6/(2+3) = 1.2 m/s
final kinetic energy = (1/2)(m1+m2)v2 =(1/2)×5×1.2×1.2 = 3.6 kgm/s
loss in kinetic energy = 6-3.6 = 2.4 kgm/s
Answered by Expert
7th April 2018,
7:26 PM
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