Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

a 2m wide truck is moving with a uniform speed of 8m/s along a straight horizontal road. a pedestrian starts crossing the road at an instant when the truck is 4m away from him. the minimum constant velocity with which he should run so as to avoid the accident
 
 

Asked by jaychandran1967 20th December 2017, 11:46 AM
Answered by Expert
Answer:
pedestrian is 4 m away when he want to cross the road. Hence if the truck moves with 8 m/s speed it will take 0.5 s to reach pedastrian.
 
During this 0.5 s, pedastrian has to cross the width of truck which is 2 m. Hence the required minimum speed = 2/0.5 = 4 m/s
Answered by Expert 20th December 2017, 1:46 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Free related questions

JEE QUESTION ANSWERS

Chat with us on WhatsApp