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a 20g ball hits a wall at 45º angle with a speed of 15m/s and rebounds perpendicular to the direction of incidence with same speed .Find the impulse received by the ball

 

Asked by SUMITA 24th May 2019, 9:19 AM
Answered by Expert
Answer:
The impulse is given by 
F d t equals m triangle V
Here we are assuming that the collision with the wall is purely elastic. As the object is moving in 2D we will analyse the motion horizontally and vertically seperately.
Vertical momentum before collision
 
 p subscript i equals 0.02 cross times 15 cross times cos 45 to the power of 0 j
Horizontal momentum before collision
p subscript i equals 0.02 cross times 15 cross times cos 45 to the power of 0 i
 
After collision
vertical 
p subscript f equals 0.02 cross times 15 cross times cos 45 to the power of 0 j
Horizontal
p subscript f equals negative 0.02 cross times 15 cross times cos 45 to the power of 0 i
Therefore
Fdt=p subscript f minus p subscript i
No change in vertical momentum before and after collision hence change in vertical momentum would be zero. 
The change in horizontal momentum is
 p subscript f minus p subscript i equals 0.02 cross times 15 cross times cos 45 to the power of 0 i minus open parentheses negative 0.02 cross times 15 cross times cos 45 to the power of 0 i close parentheses
Impulse=fraction numerator 3 square root of 2 over denominator 10 end fraction k g m divided by s
Answered by Expert 24th May 2019, 12:09 PM
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