Given,pulley is smooth and string is light.One side of pulley has a mass of 50kg and other side has a box inside which there is a man standing on a weighing machine (mass of box+weighing machine=100kg) and mass of man=50kg.what is the reading of weighing machine?
Asked by m.nilu
18th July 2018,
5:42 PM
Answered by Expert
Answer:
Acceleration a of the box that contains weighing machine and man is given by, a = 
Free body diagram showing the forces acting between man and weighing machine is shown in figure.
Let W be the weight of man (50×g) and Fms be the force acting on man by weighing machine
By Newton's law, we have, W - Fms = m × a ; hence Fms = W - m×a = 50×9.8 - 50×4.9 = 245 N
Hence the weighing machine reading is 245 Newton or 25 kgf
Answered by Expert
13th August 2018,
2:52 PM
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