5mol PCl5 (g) and one mol N2 gas is placed in a closed vessel.At equilibrium PCl5(g) decomposes by 20% and total pressure into the container is found to be 1atm .The Kp for equilibrium PCl5(g)==PCl3(g)+Cl2(g).
Asked by m.nilu
24th October 2018,
2:19 PM
Answered by Expert
Answer:
given, mole of PCl5 = 5 mol
mole of N2 = 1 mol,
Now, when PCl5 is heated, its 20% dissociated,
PCl5(g) ----------------> PCl3(g) + Cl2(g)
t=o, 5 mole 0 0
t , 5- (5*0.2) 5*0.2 5*0.2
= 4 =1 =1
Now, Total moles = mole of PCl5 + mole of PCl + mole of Cl2 + mole of N2
= 4 + 1 + 1 + 1 = 7 mole
So, mole fraction of PCl5 = 4/7
mole fraction of PCl3 = 1/7
mole fraction of Cl2 = 1/7
Now, from Dalton's law of partial pressure
PPCl5 = mole fraction of PCl5 * Total pressure
= (4/7) * 1 = 4/7 atm
Similarly, PPCl3 = 1/7 atm
PCl2 = 1/7 atm
Therefore, Kp = (PCl2 * PPCl3) / PPCl5
= (1/7 * 1/7)/(4/7)
= 1/28 atm
Answered by Expert
28th October 2018,
4:14 PM
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