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Asked by StarBoy 15th December 2018, 2:25 PM
Answered by Expert
Answer:
It is asked in the posting to answer (ii) and (iii) . To answer (iii) Figure is not visible , hence we are unable to answer (iii).
 
So only (ii) is answered below.
 
3 μF capacitor is connected to 90V battery through 200Ω resistance.
Hence charge acquired by the capacitor will be 3×90 = 270 μC.
 
6 μF capacitor is connected across 100Ω resistance. Once the 3 μF capacitor is charged there will not be any current flow
through this 100Ω resistor, hence ther will not be any potential drop across this 100Ω resistor.
Hence 6 μF capacitor will not be charged
Answered by Expert 18th December 2018, 10:28 AM
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