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(1) How is Freundlich Adsorption Isotherm used to correlate the experimental facts regarding the adsorption of gas at low, high  and  intermediate pressure ?

Asked by sudhanshubhushanroy 6th March 2018, 5:50 AM
Answered by Expert
Answer:
Freundlich Adsorption Isotherm:

The variation on extent or adsorption (x/m) when pressure (P) was given mathematically byFreundlich.
The following observations can be easily made:(i) At low pressure, the graph is the almost straight line which indicates the x/m is directly proportional to the pressure.
This may be expressed as:

x over m proportional to space p space space space space space o r space space space space space space space space x over m space equals space k p
 
(ii) At high pressure, the graph becomes almost constant which mean that x/m becomes independent of pressure.
This may be expressed as:

x over m space equals space c o n s tan t space space space space o r space space space space space x over m space proportional to space space p to the power of o space space space left parenthesis because space p to the power of o space equals space 1 right parenthesis
space
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space o r
x over m equals space p k to the power of o space equals space k comma space space a s space p to the power of o space equals space 1 space
 
(pressure raised to the power zero = 1)
 
(iii) This, in the intermediate range of pressure, x/m will depend upon the power of pressure which lies between 0 and 1 i.e., the fractional power of pressure.
This may be expressed as:

x over m space proportional to space p to the power of 1 over n end exponent space semicolon space space x over m space equals space k p to the power of 1 over n end exponent
Calculation of k and n of adsorption isotherm: The constant k and n can be determined as explained below: Taking logarithms on both sides of the equation space space x over m space equals space k p to the power of 1 over n end exponent
log space x over m space equals space log space k space plus space 1 over n space log space p


Figure 5-plot of log (x/m) Vs log p Thus, if we plot a graph-3 between log (x/m) and log p, a straight line will be obtained.
The slope of the line is equal to 1/n and the intercept is equal to log k.
Answered by Expert 6th March 2018, 10:29 AM
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