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# Frank Modern Certificate Solution for Class 9 Physics Chapter 6 - Light

## Frank Textbook Solutions Chapter 6 - Light

Frank Textbook Solutions are considered extremely helpful for solving difficult questions in the ICSE Class 9 Physics exam. TopperLearning Textbook Solutions are compiled by our subject experts. Herein, you can find all the answers to the questions of   Chapter 6 - Light for the Frank textbook.

Frank Textbook Solutions for class 9  are in accordance with the latest ICSE syllabus, and they are amended from time to time to be most relevant. Our free Frank Textbook Solutions for ICSE Class 9 Physics will give you deeper insight on the chapters and will help you to score more marks in the final examination. ICSE Class 9 students can refer to our solutions while doing their homework and while preparing for the exam.

Exercise/Page

## Frank Modern Certificate Solution for Class 9 Physics Chapter 6 - Light Page/Excercise 261

Solution 1

Convex mirror has a wider field of view.

Solution 2

Convex mirror always produces an erect image of the object.

Solution 3

Convex mirror is used in vehicles to see the traffic on rear side.

Solution 4

We will use convex mirror to see an enlarged image of our face.

Solution 5

Image of object placed at a long distance in front of a convex mirror is formed at principal focus. Radius of curvature of convex mirror is 20 cm.
Focal length of convex mirror = radius of curvature/2.
Focal length of convex mirror = 20/2 = 10 cm.
So image will form at principal focus 10 cm away from pole.

Solution 6

Concave mirror can produce real and diminished image of the object.

Solution 7

The distance of the principal focus from the pole of the mirror is called the focal length of the mirror.

Solution 8

The mirror having +20 cm as its focal length is a convex mirror because focal length is taken positive only in case of convex mirror.

Solution 9

The focal length of plane mirror is infinity.

Solution 10

The mirror having -15 cm as its focal length is a concave mirror because focal length is taken negative only in case of concave mirror.

Solution 11

Principal axis is the straight line passing through the pole and the centre of curvature.

Solution 12

Linear magnification is defined as the ratio of the height of the image to the height of the object. It is taken to be positive for an image to be virtual and erect and negative when image is real and inverted.
Magnification = height of image / height of object.

Solution 13

Pole is the centre of the reflecting surface, in this case spherical mirror.

Solution 14

Centre of curvature is the centre of the imaginary sphere to which the mirror belongs.

Solution 15

Three characteristics of light are:-
(a). Light waves can travel through vacuum.
(b). Light waves are transverse waves.
(c). The velocity of light in vacuum is 3 x 108 m/s.

Solution 16

Three distinctions between light and sound waves are
(i) Light waves can travel through vacuum while sound waves cannot.
(ii) Light waves are transverse waves while sound waves are longitudinal waves.
(iii) The velocity of light in air is 3 x 108 m/s while the speed of light in air is just about 330 m/s.

Solution 17

(i) When position of object is at infinity, concave mirror forms a point and Real image at Focus point.
(ii) When position of object is beyond C, concave mirror forms a Diminished, Real and inverted image between F and C.
(iii)When position of object is at C, concave mirror forms a Magnified, Real and inverted image at C.

Solution 18

Image formed by a convex mirror is always Diminished, Virtual and Erect.

Solution 19

Concave mirrors are used in reflecting microscope, in shaving and make up glasses and in ophthalmoscope.

Solution 20

(i) The distance from the pole in the direction of incident ray is taken positive.
(ii) The distance from the pole in the direction opposite to the incident ray is taken negative.

Solution 21

Mirror formula is the relation between the focal length f of the mirror, the distance u of the object from the pole of the mirror, and the distance v of the image from the pole.
Mirror formula is
1/v +1/u = 1/f.
Linear magnification is defined as the ratio of the height of the image to the height of the object. It is taken to be positive for an image to be virtual and erect and negative when image is real and inverted.
Magnification = height of image / height of object.

Solution 22

Mirror formula is the relation between the focal length f of the mirror, the distance u of the object from the pole of the mirror, and the distance v of the image from the pole.
Mirror formula is
1/v +1/u = 1/f.
Size of body = 1.5 m.
Magnification of body= 1.5.
Magnification = height of image / height of object.
Height of image = magnification �height of object.
Height of image = 1.5�1.5= 2.25 m.

Solution 23

Linear magnification is defined as the ratio of the height of the image to the height of the object. It is taken to be positive for an image to be virtual and erect and negative when image is real and inverted.
Magnification produced by concave mirror is:
Magnification = height of image / height of object.
It is a pure ratio and does not have any units.

Solution 24 Solution 25

A smooth and polished surface causes regular reflection while a rough and unpolished surface causes irregular reflection.

Solution 26

When rays of light fall on a surface, they are turned back into the same medium in accordance with some definite laws. This process is known as reflection.
Reflection obeys following two laws
(a). The incident ray, the reflected ray, and the normal at the point of incidence, all lie in the same plane.
(b). The angle of incidence and the angle of reflection are always equal.

Solution 27

You can distinguish between plane mirror, a concave mirror, and a convex mirror without touching them. When you look into these mirrors by bringing your face close to each mirror, they will produce an image of your face of different types.
A plane mirror will produce an image of the same size as your face.
A concave mirror will produce a magnified image of your face.
A convex mirror will produce Diminished image of your face.

Solution 28

You can distinguish between a concave mirror and a convex mirror without touching them. When you look into these mirrors by bringing your face close to each mirror, they will produce an image of your face of different types.
A concave mirror will produce a magnified image of your face.
A convex mirror will produce Diminished image of your face.

## Frank Modern Certificate Solution for Class 9 Physics Chapter 6 - Light Page/Excercise 262

Solution 29 Solution 30

Uses of concave mirror:
(i) Concave mirrors are used in reflecting microscope
(ii) Concave mirrors are used in shaving and make up glasses.
Uses of convex mirror: Convex mirrors are used as a rear view mirror in automobiles as it provides a wider view of following traffic.

Solution 31

We can see the reflection of our face on a polished table top because a regular reflection occurs in case of a polished surface while on a unpolished table top irregular reflection occurs which make image of our face unclear.

Solution 32

(i)The angle of incidence is the angle made by the incident ray with the plane mirror. {FALSE}
Correct statement is the angle of incidence is the angle made by the incident ray with the normal to the surface of plane mirror.
(ii) If a ray of light incident on a plane mirror is such that it makes an angle of 30o with the normal, then the angle of reflection is 60o.{FALSE}
Correct statement is if a ray of light incident on a plane mirror is such that it makes an angle of 30o with the normal, then the angle of reflection is 30o.
(iii)If the incident ray makes an angle of Xo with the normal, then the angle between the incident ray and reflected ray is 2Xo. {TRUE}
(iv)The image formed in a plane mirror is real, erect and same size as that of the object. {FALSE}
Correct statement is the image formed in a plane mirror is virtual, erect and same size as that of the object.

Solution 33 Solution 34 Solution 35

The image formed by a plane mirror is erect and virtual. It is a laterally inverted image. The image formed is of the same size as that of the object. Also, the image and the object are equidistant from the mirror.

Solution 36 Solution 37

Given, distance of boy from the mirror = 3 m
(a) Distance of image from mirror = distance of boy from the mirror = 3 m
Distance between boy and his image = distance of boy from the mirror + distance of image from mirror = 3+3 = 6 m
(b) Now, distance of boy from the mirror = 4 m
Distance of image from mirror = 4 m
Distance between boy and his image = distance of boy from the mirror + distance of image from mirror = 4+4 = 8m.

Solution 38

Periscope is used to see over the top of an obstacle. It is also used in submarines for observing for movement of ships. It can be used from the trenches for observing the movement on the surface of earth.

## Frank Modern Certificate Solution for Class 9 Physics Chapter 6 - Light Page/Excercise 263

Solution 39 Solution 40

(a) Pole is the centre of the reflecting surface, in this case spherical mirror.
(b) Centre of curvature is the centre of the imaginary sphere to which the mirror belongs
(c) Principal focus of a spherical mirror is a point on the principal axis of the mirror, where all the rays travelling parallel to the principal axis and close to it after reflection from the mirror, converge to or appear to diverge from.
(d) Principal axis is the straight line passing through the pole and the centre of curvature.
(e) Focus of a concave mirror is a point on the principal axis of the mirror, where all the rays travelling parallel to the principal axis and close to it after reflection from the mirror converge to that point.
(f) Normal to the surface of a mirror at any point is the straight line at right angle to the tangent drawn at that point.

Solution 41 Solution 42 Solution 43 Solution 44 Solution 45 Solution 46 ## Frank Modern Certificate Solution for Class 9 Physics Chapter 6 - Light Page/Excercise 264

Solution 47 Solution 48 Solution 49 Solution 50 ## Browse Study Material

TopperLearning provides step-by-step solutions for each question in each chapter in the Frank textbook recommended by ICSE schools. Access Chapter 6 - Light here. Our Frank Textbook Solutions for ICSE Class 9 Physics are designed by our subject matter experts. These solutions will help you to revise the whole chapter, so you can clear your fundamentals before the examination.

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ICSE IX - Physics

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