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# Frank Modern Certificate Solution for Class 9 Physics Chapter 8 - Electricity and Magnetism - Current Electricity

## Frank Textbook Solutions Chapter 8 - Electricity and Magnetism - Current Electricity

Frank Textbook Solutions are considered extremely helpful for solving difficult questions in the ICSE Class 9 Physics exam. TopperLearning Textbook Solutions are compiled by our subject experts. Herein, you can find all the answers to the questions of   Chapter 8 - Electricity and Magnetism - Current Electricity for the Frank textbook.

Frank Textbook Solutions for class 9  are in accordance with the latest ICSE syllabus, and they are amended from time to time to be most relevant. Our free Frank Textbook Solutions for ICSE Class 9 Physics will give you deeper insight on the chapters and will help you to score more marks in the final examination. ICSE Class 9 students can refer to our solutions while doing their homework and while preparing for the exam.

Exercise/Page

## Frank Modern Certificate Solution for Class 9 Physics Chapter 8 - Electricity and Magnetism - Current Electricity Page/Excercise 312

Solution 1

The flow of electrons in a particular direction in a conductor is called an electric current.

Solution 2

An electric cell is the source of electric current in which chemical energy changes to electrical energy.

Solution 3

The charge on an electron is -1.6 x 10-19C.

Solution 4

The constituents of cell are two electrodes in the form of conducting rods immersed in the solution called electrolyte.

Solution 5

(i) S. I unit of electric current is Ampere
(ii) S.I unit of potential difference is volt.
(iii) S.I unit of resistance is ohm.

Solution 6

I = 1A
T = 1s.
I = Q/t = ne/t
So, n = I . t / e = 1 . (1 / 1.6 x 10-19) = 6.25 x 1018 electrons.

Solution 7

I = Q/t  = 0.7 / 7 = 0.1 Ampere.

Solution 8

Rheostat is used to control the current in the circuit.

## Frank Modern Certificate Solution for Class 9 Physics Chapter 8 - Electricity and Magnetism - Current Electricity Page/Excercise 313

Solution 9

Rheostat is the variable name of electrical resistance.

Solution 10

Switch is used to put the current on and off in the circuit.

Solution 11 Solution 12

I = Q/ t So, Q = I .t  = 1.2 x 3.0  = 3.6 C.

Solution 13

A - is a voltmeter to measure the potential difference, B is an electric resistance to control the current in the circuit , C is the ammeter to measure the magnitude of an electric current, D is cell to provide electric current in circuit, E is an electric key to on and off the circuit, F is the rheostat to control the current in circuit.

Solution 14

The slope of the graph represents that with current flowing through a conductor is directly proportional to the potential difference applied the resistance of conductor is constant.

Solution 15

Potential difference between two conductors is defined as the amount of work done in moving the unit positive charge from one conductor to another through the wire.

Solution 16

Yes, electric current is a scalar quantity.

Solution 17

The electric resistance of the wire depends on the following factors :
(i)The length of the wire.
(ii)The area of cross-section of the wire.
(iii)The temperature of the wire.
(iv)The material of the wire.

Solution 18

The S.I unit of resistance is ohm.

Solution 19

If another bulb is connected in series then the resistance of the wire will increase.
If another bulb is connected in parallel then resistance will decrease.

Solution 20

V = I R.

Solution 21

The resistance of the wire is 2 ohms if a current of 1 ampere flows through it when the potential difference across it is 2 volt.

Solution 22

The current I = V/R = 14/28 = 0.5 Ampere.

Solution 23

The factors on which resistance of the wire depends are :
(i) The length of the wire , resistance is directly proportional to the length of wire.
(ii) The cross-section of the wire , resistance is inversely proportional to the cross-section of the wire.
(iii) The temperature of the wire , resistance of wire is directly proportional to the temperature of the wire.
(iv) The material of the wire (good conductors possess less resistance.)

Solution 24

W = V.Q = 6. 3 = 18Joule.

Solution 25

The resistance of the conductor is the property due to which it opposes the flow of current in it.

Solution 26

The potential difference between two points is 1 volt if the work done in transferring 1 coulomb of charge from one point to another point is 1 joule.

## Browse Study Material

TopperLearning provides step-by-step solutions for each question in each chapter in the Frank textbook recommended by ICSE schools. Access Chapter 8 - Electricity and Magnetism - Current Electricity here. Our Frank Textbook Solutions for ICSE Class 9 Physics are designed by our subject matter experts. These solutions will help you to revise the whole chapter, so you can clear your fundamentals before the examination.

# Text Book Solutions

ICSE IX - Physics

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