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Frank Modern Certificate Solution for Class 9 Mathematics Chapter 19 - Quadrilaterals

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Frank Textbook Solutions Chapter 19 - Quadrilaterals

Frank Textbook Solutions are considered extremely helpful for solving difficult questions in the ICSE Class 9 Mathematics exam. TopperLearning Textbook Solutions are compiled by our subject experts. Herein, you can find all the answers to the questions of   Chapter 19 - Quadrilaterals for the Frank textbook.

Frank Textbook Solutions for class 9  are in accordance with the latest ICSE syllabus, and they are amended from time to time to be most relevant. Our free Frank Textbook Solutions for ICSE Class 9 Mathematics will give you deeper insight on the chapters and will help you to score more marks in the final examination. ICSE Class 9 students can refer to our solutions while doing their homework and while preparing for the exam.

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Exercise/Page

Frank Modern Certificate Solution for Class 9 Mathematics Chapter 19 - Quadrilaterals Page/Excercise 19.1

Solution 1(a)

Solution 1(b)

Solution 1(c)

Solution 1(d)

Solution 1(e)

Solution 2

Solution 3

 

 

Solution 4

Solution 5

Solution 6

Solution 7

Solution 8

Solution 9

Solution 10

Solution 11

Solution 12

Solution 13

 

Construction: Join PR.

 

 

Solution 14

Solution 15

Frank Modern Certificate Solution for Class 9 Mathematics Chapter 19 - Quadrilaterals Page/Excercise 19.2

Solution 1

Solution 2

Solution 3

Solution 4

Solution 5

Solution 6

Solution 7

Solution 8

Solution 9

Solution 10

Solution 11

Solution 12

Solution 13(a)

 

 

Solution 13(b)

 

 

Solution 13(c)

 

 

Solution 14

Solution 15(a)

Construction:

Join BS and AQ.

Join diagonal QS.

 

 

Solution 15(b)

Construction:

Join BS and AQ.

Join diagonal QS.

 

 

Solution 16(a)

Construction:

Draw SM PQ and RN PQ

 

Solution 17

 

 

Solution 18

 

Let ABCD be a quadrilateral, whose diagonals AC and BD bisect each other at right angle.

i.e. OA = OC, OB = OD

And, AOB = BOC = COD = AOD = 90°

To prove ABCD a rhombus, we need to prove ABCD is a parallelogram and all sides of ABCD are equal.

Now, in ΔAOD and DCOD

OA = OC  (Diagonal bisects each other)

AOD = COD (Each 90°)

OD = OD   (common)

∴ΔAOD ≅ΔCOD  (By SAS congruence rule)

AD = CD  ….(i)

Similarly, we can prove that

AD = AB and CD = BC ….(ii)

From equations (i) and (ii), we can say that

AB = BC = CD = AD

Since opposite sides of quadrilateral ABCD are equal, so, we can say that ABCD is a parallelogram.

Since all sides of a parallelogram ABCD are equal, so, we can say that ABCD is a rhombus.

Solution 19

Consider ABCD is a kite.

Then, AB = AD and BC = DC

 

 

 

Solution 20

 

 

TopperLearning provides step-by-step solutions for each question in each chapter in the Frank textbook recommended by ICSE schools. Access Chapter 19 - Quadrilaterals here. Our Frank Textbook Solutions for ICSE Class 9 Mathematics are designed by our subject matter experts. These solutions will help you to revise the whole chapter, so you can clear your fundamentals before the examination.

Text Book Solutions

ICSE IX - Mathematics

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