Frank Modern Certificate Solution for Class 9 Mathematics Chapter 15 - Mid-point and Intercept Theorems
Frank Textbook Solutions Chapter 15 - Mid-point and Intercept Theorems
Frank Textbook Solutions are considered extremely helpful for solving difficult questions in the ICSE Class 9 Mathematics exam. TopperLearning Textbook Solutions are compiled by our subject experts. Herein, you can find all the answers to the questions of Chapter 15 - Mid-point and Intercept Theorems for the Frank textbook.
Frank Textbook Solutions for class 9 are in accordance with the latest ICSE syllabus, and they are amended from time to time to be most relevant. Our free Frank Textbook Solutions for ICSE Class 9 Mathematics will give you deeper insight on the chapters and will help you to score more marks in the final examination. ICSE Class 9 students can refer to our solutions while doing their homework and while preparing for the exam.
Frank Modern Certificate Solution for Class 9 Mathematics Chapter 15 - Mid-point and Intercept Theorems Page/Excercise 15.1
Let us draw a diagonal AC which meets PQ at O as shown below:
Construction: Draw DS ∥ BF, meeting AC at S.
Frank Modern Certificate Solution for Class 9 Mathematics Chapter 15 - Mid-point and Intercept Theorems Page/Excercise 15.2
The figure is as below:
Let ABCD be a quadrilateral where P, Q, R, S are the midpoints of sides AB, BC, CD, DA respectively.
Diagonals AC and BD intersect at right angles at point O. We need to show that PQRS is a rectangle
Note: This question is incomplete.
According to the information given in the question,
F could be any point on BC as shown below:
So, this makes it impossible to prove that DP = DE, since P too would shift as F shift because P too would be any point on DE as F is.
Note: If we are given F to be the mid-point of BC, the result can be proved.
From the figure EF ∥ AB and E is the midpoint of BC.
Therefore, F is the midpoint of AC.
Here EF ∥ BD, EF = BD as D is the midpoint of AB.
BE ∥ DF, BE = DF as E is the midpoint of BC.
Therefore BEFD is a parallelogram.
Remark: Figure modified
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