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# Frank Modern Certificate Solution for Class 9 Mathematics Chapter 15 - Mid-point and Intercept Theorems

## Frank Textbook Solutions Chapter 15 - Mid-point and Intercept Theorems

Frank Textbook Solutions are considered extremely helpful for solving difficult questions in the ICSE Class 9 Mathematics exam. TopperLearning Textbook Solutions are compiled by our subject experts. Herein, you can find all the answers to the questions of   Chapter 15 - Mid-point and Intercept Theorems for the Frank textbook.

Frank Textbook Solutions for class 9  are in accordance with the latest ICSE syllabus, and they are amended from time to time to be most relevant. Our free Frank Textbook Solutions for ICSE Class 9 Mathematics will give you deeper insight on the chapters and will help you to score more marks in the final examination. ICSE Class 9 students can refer to our solutions while doing their homework and while preparing for the exam.

Exercise/Page

## Frank Modern Certificate Solution for Class 9 Mathematics Chapter 15 - Mid-point and Intercept Theorems Page/Excercise 15.1

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Solution 3(a)

Solution 3(b)

Solution 3(c)

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Solution 14

Solution 15(a)

Let us draw a diagonal AC which meets PQ at O as shown below:

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Solution 18

Construction: Draw DS BF, meeting AC at S.

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Solution 24

## Frank Modern Certificate Solution for Class 9 Mathematics Chapter 15 - Mid-point and Intercept Theorems Page/Excercise 15.2

Solution 1

Solution 2

Solution 3

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Solution 5

The figure is as below:

Let ABCD be a quadrilateral where P, Q, R, S are the midpoints of sides AB, BC, CD, DA respectively.

Diagonals AC and BD intersect at right angles at point O. We need to show that PQRS is a rectangle

Solution 6

Note: This question is incomplete.

According to the information given in the question,

F could be any point on BC as shown below:

So, this makes it impossible to prove that DP = DE, since P too would shift as F shift because P too would be any point on DE as F is.

Note: If we are given F to be the mid-point of BC, the result can be proved.

Solution 7

From the figure EF AB and E is the midpoint of BC.

Therefore, F is the midpoint of AC.

Here EF BD, EF = BD as D is the midpoint of AB.

BE DF, BE = DF as E is the midpoint of BC.

Therefore BEFD is a parallelogram.

Remark: Figure modified

Solution 8

Solution 9

## Browse Study Material

TopperLearning provides step-by-step solutions for each question in each chapter in the Frank textbook recommended by ICSE schools. Access Chapter 15 - Mid-point and Intercept Theorems here. Our Frank Textbook Solutions for ICSE Class 9 Mathematics are designed by our subject matter experts. These solutions will help you to revise the whole chapter, so you can clear your fundamentals before the examination.

# Text Book Solutions

ICSE IX - Mathematics

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