Frank Modern Certificate Solution for Class 9 Chemistry Chapter 2 - Study of Gas Laws
Frank Textbook Solutions Chapter 2 - Study of Gas Laws
Frank Textbook Solutions are considered extremely helpful for solving difficult questions in the ICSE Class 9 Chemistry exam. TopperLearning Textbook Solutions are compiled by our subject experts. Herein, you can find all the answers to the questions of Chapter 2 - Study of Gas Laws for the Frank textbook.
Frank Textbook Solutions for class 9 are in accordance with the latest ICSE syllabus, and they are amended from time to time to be most relevant. Our free Frank Textbook Solutions for ICSE Class 9 Chemistry will give you deeper insight on the chapters and will help you to score more marks in the final examination. ICSE Class 9 students can refer to our solutions while doing their homework and while preparing for the exam.
Frank Modern Certificate Solution for Class 9 Chemistry Chapter 2 - Study of Gas Laws Page/Excercise 21
An ideal gas can be characterized by three state variables:
(i) Absolute pressure (P),
(ii) Volume (V), and
(iii) Absolute temperature (T).
Kelvin zero is -273.15oC.
The standard temperature and pressure (STP) by general convention are 0OC(273 K) and 1 atm(760 mm Hg).
(a) The value of standard temperature is (i) 0oC and (ii) 273 K
(b)The value of standard pressure is (i) 1 atm, (ii) 760 mm of Hg, (iii)76 cm of Hg, (iv)760 torr
There is simultaneous effect of temperature and pressure changes on the volume of a given mass of a gas. So, when stating the volume of a gas, the pressure and temperature should also be given.
Frank Modern Certificate Solution for Class 9 Chemistry Chapter 2 - Study of Gas Laws Page/Excercise 22
(a) Volume of a gas would be reduced to zero at 0 K (-2730C).All temperatures on the Kelvin scale are positive, so Kelvin scale has been adopted for chemical calculation.
(b) At absolute zero temperature, volume of a gas would be reduced to zero. Theoretically,this is the lowest temperature that can be reached. At this temperature all molecular motions cease. Thus, practically this temperature is impossible to attain because on cooling gases liquefy and Charles' law is no more applicable.
(c) According to combined gas law equation, there is simultaneous effect of temperature and pressure changes on the volume of a given mass of a gas. So, when stating the volume of a gas, the pressure and temperature should also be given.
We trap a definite quantity of air in the closed vessel. At any point, the pressure on the air is equal to the atmospheric pressure plus the pressure due to the excess mercury column in the open end tube. By pouring mercury in the tube, we increase the pressure on the air and measure its volume under that pressure. We thus obtain a set of data for the volume of a fixed mass of air under different pressures.
For a given mass of air at constant temperature, the following observations are made-
(i) The volume of air decreases with increasing pressure and vice versa.
(ii) The proportion by which the volume decreases or increases is the same by which the pressure increases or decreases.
(a) Pressure will also be doubled.
(b) Pressure will be double.
(b) absolute zero
(c) absolute temperature
(d) the average kinetic energy
As weather balloon go higher into the atmosphere, the air becomes less dense, so air pressure drops. Because of this, the air that is already inside the balloon expands to cope with the difference in pressure. The end result is that the balloon expands making it larger.
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