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# Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 5 - Heat

## Frank Textbook Solutions Chapter Unit - 5 - Heat

Frank Textbook Solutions are considered extremely helpful for solving difficult questions in the ICSE Class 10 Physics exam. TopperLearning Textbook Solutions are compiled by our subject experts. Herein, you can find all the answers to the questions of   Chapter Unit - 5 - Heat for the Frank textbook.

Frank Textbook Solutions for class 10 are in accordance with the latest ICSE syllabus, and they are amended from time to time to be most relevant. Our free Frank Textbook Solutions for ICSE Class 10 Physics will give you deeper insight on the chapters and will help you to score more marks in the final examination. ICSE Class 10 students can refer to our solutions while doing their homework and while preparing for the exam.

Exercise/Page

## Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 5 - Heat Page/Excercise 259

Solution 1

(a)J/kg oC
(b)2000 / (4 x 3) J/kg oC
(c)AB and CD
(d)Latent heat is emitted
(e)The first time when temperature is constant represents change of state from solid to liquid and the second time temperature is constant represents change of state from liquid to vapour.

## Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 5 - Heat Page/Excercise 260

Solution 2

(a)Heat capacity of a body is the quantity of heat required to raise its temperature by 1oC. It depends upon the mass and the nature of the body.
Units: J/oC or calorie/oC
(b)Change in temperature = (50-30) = 20oC
Amount of heat required, Q = m x C x ?T
= 0.5 x 4200 x 20 = 42000 J

Solution 3

(a)This means that 390 J of heat is required to raise the temperature of 1kg of copper by 1oC.
(b)Change in temperature = (100-30) = 70oC = 70 K
Amount of heat given out, Q = m x C x T
= 0.6 x 900 x 70 = 37800 J

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## Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 5 - Heat Page/Excercise 261

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Solution 18

(a)    Ice melts under pressure. So, when the steel blades of the skates pressed on the ice, the ice melts. The water formed makes the skates slide easily over the ice, reducing friction. So, when we are skating on ice, we are skating on a thin film of water, which acts like lubricating oil. Nothing such happens in case of glass.
(b)    Sand improves the friction between car tyres and the road, so cars don't skid on icy surfaces. Salt is spread so as to decrease the melting point of ice. Ice on the roads melt, making the roads less slippery.
(c)    Steam burn is worse than a hot water burn because 1 g of steam gives out 540 calories of additional heat.
(d)    Lumps of ice cool better than cold water because each gram of ice requires additional 80 calories of heat to get converted into water. Hence, cooling capacity of lumps of ice is more than cold water.

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## Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 5 - Heat Page/Excercise 262

Solution 32

Steam at 100oC will produce more severe burns because every gram of steam gives out 2260 J of heat energy while condensing. This much amount of heat is additional to the heat contained in one gram of boiling water.

Solution 33

Ice cream appears colder to mouth than water at 0oC because it can extract approximately 80 cal/g (latent heat of fusion of ice)more heat from as compared to water at 0 oC.

Solution 34

Although both ice cubes and iced water are at 0oC but ice cubes cool more quickly because each gram of ice requires additional 80 calories of heat to get converted into water at the same temperature, i.e., at 0oC. Hence, the cooling capacity of ice cubes is more than that of iced water.

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Solution 37

1 gram of ice at 0oC requires 80 calories of heat to get converted into 1 gram of water at 0oC. So, water has more heat.

Solution 38

1 gram of water at 100oC requires 540 calories of heat to get converted into 1 gram of steam at 100oC. So, steam has more heat.

Solution 39

1 gram of ice at 0oC requires additional 80 calories of heat to get converted into water at 0oC. Then, heat is provided to raise the temperature to 10oC. Therefore, ice requires more heat than water and the additional heat is known as 'Latent heat of fusion of ice'.

Solution 40

Pressure cooker increases the pressure and hence the boiling point increases. So, the boiling point becomes greater than 100oC.

## Browse Study Material

TopperLearning provides step-by-step solutions for each question in each chapter in the Frank textbook recommended by ICSE schools. Access Chapter Unit - 5 - Heat here. Our Frank Textbook Solutions for ICSE Class 10 Physics are designed by our subject matter experts. These solutions will help you to revise the whole chapter, so you can clear your fundamentals before the examination.

# Text Book Solutions

ICSE X - Physics

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