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Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 1 - Force, Work, Energy and Power

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Frank Textbook Solutions Chapter Unit - 1 - Force, Work, Energy and Power

Frank Textbook Solutions are considered extremely helpful for solving difficult questions in the ICSE Class 10 Physics exam. TopperLearning Textbook Solutions are compiled by our subject experts. Herein, you can find all the answers to the questions of   Chapter Unit - 1 - Force, Work, Energy and Power for the Frank textbook.

Frank Textbook Solutions for class 10 are in accordance with the latest ICSE syllabus, and they are amended from time to time to be most relevant. Our free Frank Textbook Solutions for ICSE Class 10 Physics will give you deeper insight on the chapters and will help you to score more marks in the final examination. ICSE Class 10 students can refer to our solutions while doing their homework and while preparing for the exam.

 

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Exercise/Page

Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 1 - Force, Work, Energy and Power Page/Excercise 47

Solution 1

Force

Solution 2

Yes

Solution 3

Joule

Solution 4

Work

Solution 5

1N, 1m in its own direction

Solution 6

When no net force is applied, the work done which is the dot product of force and displacement is zero.

Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 1 - Force, Work, Energy and Power Page/Excercise 48

Solution 7

The work done is zero because the displacement is zero.

Solution 8


Solution 9

Work is a scalar quantity because it is a measure of transfer of energy without indicating any direction.

Solution 10

Solution 11

The work done by the gravitational force of the earth on a satellite revolving around the earth is zero because the motion of the satellite is perpendicular to the force at every point.

Solution 12

Solution 13

Solution 14

The work done against gravity is zero when a body is moved horizontally along a frictionless surface because the force of gravity is perpendicular to the displacement in this case.

Solution 15

'Work' is said to be done when the applied force makes the body move i.e., there is a displacement of body.
It is equal to the product of force and the displacement of the point of application of the force in the direction of force.

Solution 16

Work done depends upon:
(i) the magnitude and direction of the applied force, and
(ii) the displacement it produces.

Solution 17

Yes, we perform work against gravity.

Solution 18

The angle should be 90o.

Solution 19

This is because at each point of the circular path, the displacement is perpendicular to the force, which is directed towards the centre, along the radius.

Solution 20

When the angle between the direction of motion and that of the force is 90°;
W = Fd cos 90° = 0
When the angle between the direction of motion and that of the force is 0°;
W = Fd cos 0° = Fd
Hence in the second case, when the angle is 0°; the work done is more.

Solution 21

The displacement of the man and suitcase is along the horizontal direction. Thus, the angle between the displacement and the force of gravity is 90°;
Thus, W = Fd cos 90° = 0
Hence, no work is done against gravity in this case.

Solution 22

When a body moves along a circular path, work done by the gravitational force towards the centre of the path is zero, because the displacement in this case is normal to the gravitational force.

Solution 23

The work done by the gravitational force of the sun on earth during its motion around the sun is zero because at every point, the displacement of earth is perpendicular to the gravitational force of sun i.e.,
 W = Fd cos 900 = 0

Solution 24

A kilojoule of work is said to done when a force of 1 newton displaces a body through 1000 metres in its own direction.
1 kJ = 103 joules

Solution 25

1 MJ = 106 joules

Solution 26

The SI unit of work is joule.
1 joule of work is said to be done when a force of 1 newton displaces a body through 1 metre in its own direction.

Solution 27

The SI unit of work is 'joules' and the CGS unit is 'erg'.
1 joule = 107 erg
Thus the ratio is 107: 1

Solution 28

Solution 29

Solution 30

Applied force, displacement in the direction of the applied force.

Solution 31

Examples of work done:
(i) In free fall of a body of mass m, under gravity from a height h, the force of gravity (F=mg) is in the direction of displacement (=h) and the work done by the gravity is mgh.
(ii) A coolie lifting a load does work against gravity.

Solution 32

Work done depends upon:
(i) the magnitude and direction of the applied force, and
(ii) the displacement it produces.

Solution 33


Solution 34

Work done against gravity = mass x acceleration due to gravity x height
Or, W = mgh

Solution 35

The displacement of the man and box is along the horizontal direction. Thus, the angle between the displacement and the force of gravity is 900;
Thus, W = Fd cos 900 = 0
Hence, no work is done against gravity in this case; however some work is done against friction.

Solution 36

Yes, power is a scalar quantity.

Solution 37

No, every force cannot produce work. Force can produce work if the applied force cause displacement in the direction of the force.

Solution 38

Work is said to be done only when the applied force on a body makes the body move but power is the rate of doing work.
The SI unit of work is 'joules' and that of power is 'watt'.

Solution 39

(a) joule, watt
(b) power, energy
(c) work
(d) 107
(e) 746

Solution 40

Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 1 - Force, Work, Energy and Power Page/Excercise 49

Solution 41

Solution 42

Power

Solution 43

Work done depends upon the vertical height and not the path taken, hence if the boy uses a lift to reach the same vertical height, work done will be mgh.

Solution 44

Yes, for e.g. if you push a wall, you apply force on it but no work is done since the displacement is zero.

Solution 45

1 H.P. = 0.746 kW

Solution 46

Solution 47

Solution 48

Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 1 - Force, Work, Energy and Power Page/Excercise 72

Solution 1

When the resultant of a group of forces acting on the same object is zero, the forces are said to be balanced. Balanced forces do not change the speed of stationary objects. They may deform objects.

Solution 2

Yes, force is a vector quantity.

Solution 3

1 kgf = force due to gravity on 1 kg mass
      = 1 kg mass x acceleration due to gravity g in ms-2
      = g newton
1 kgf = 9.8 newton

Solution 4

The SI unit of force is 'newton'.
In CGS system, the unit of force is 'dyne'.
1 newton = 105 dyne
Therefore, ratio of SI to CGS unit of force is 105 : 1.

Solution 5

Yes, weight is a force.

Solution 6

When we kick a football at rest, it starts moving.

Solution 7

When a balloon is inflated the force of air inside changes it shape or size.

Solution 8

Effects a force can produce and examples:
1. Change the state of rest; e.g. pushing a door to open it or close it.
2. Change the state of motion; e.g. applying a force to stop the cricket ball.
3. Change the direction of motion and not speed; e.g. when a force is applied to move a body in a circular path with uniform speed there is only a change in direction of motion but speed remains constant.
4. Change both speed and direction of motion; e.g. when a body is swirled in the vertical circle its direction of motion and speed changes at every point.
5. Change the dimension; when a balloon is inflated the force of air inside changes its shape or size.

Solution 9

No

Solution 10

No

Solution 11

The turning effect produced by a force on a rigid body about a point, pivot or fulcrum is called the moment of force or torque. It is measured by the product of force and the perpendicular distance of the pivot from the line of action of force.
Moment of a force = Force x perpendicular distance of the pivot from the force.
Its SI unit is newton-metre (Nm).

Solution 12

The physical quantity is 'torque'.

Solution 13

The turning effect produced by a force on a rigid body about a point, pivot or fulcrum is called the moment of force or torque. It is measured by the product of force and the perpendicular distance of the pivot from the line of action of force.

Solution 14

Solution 15

SI unit of couple = newton
CGS unit of couple = dyne

Solution 16

No, the moment of force is a vector quantity.

Solution 17

A larger diameter provides a greater torque (= force x perpendicular distance); hence, it is easier to turn a steering wheel of a large diameter than that of a small diameter.

Solution 18

The point through which the resultant of the weights of all the particles of the body acts is called its centre of gravity

Solution 19

A body is said to be in equilibrium under the action of a number of forces, if the forces are not able to produce any change in the state of rest or of uniform motion or uniform rotation.

Solution 20

Principle of moments: If a body is in equilibrium under the action of number of force, then the sum of clockwise moments is equal to the sum of anticlockwise moments.

Solution 21

Solution 22

Solution 23

The point through which the resultant of the weights of all the particles of the body acts is called its centre of gravity

Solution 24

The centre of gravity of a uniform ring is situated at the centre of the ring.

Solution 25

The centre of gravity of a body depends upon:
(i) Body's weight
(ii) Body's shape

Solution 26

Yes, the centre of gravity of a body can be outside it. The CG of a uniform ring is at its centre, a point which is not on the body.

Solution 27

Solution 28

Centripetal force: Whenever a body is moving in a circular path with a uniform speed, its velocity is continuously changing due to change in its direction. The body thus possesses acceleration and this acceleration is called centripetal acceleration. The force which produces this acceleration is called centripetal force. It acts along the radius towards the centre of the circular path.
It is not the same as the centrifugal force.

Solution 29

Yes, force can be used to change the size and shape of the body.
Example: On squeezing toothpaste tube, its size as well as shape changes.

Solution 30

Characteristics of non-contact forces:
(i) Forces at distance are equal and opposite.
(ii) Depend upon the distance between the two objects.
(iii) Depend upon the medium between the two objects for electrical and magnetic forces but not gravitational forces.

Solution 31

Examples where force can start the motion of a body:
(i) The pulling of a cart by a rope.
(ii) Pushing a door to open it.
Examples where force can stop the motion of a body:
(i) Applying a force to stop a cricket ball.
(ii) Applying the brakes of car to stop it.

Solution 32

The physical quantity is 'torque'.
Torque may be defines as the turning effect produced by a force on a rigid body about a point, pivot or fulcrum. It is measured by the product of force and the perpendicular distance of the pivot from the line of action of force.

Solution 33

Two equal and opposite parallel forces acting along different lines on a body constitute a couple. Its SI unit is 'newton'.

Solution 34

The turning effect produced by a force on a rigid body about a point, pivot or fulcrum is called the moment of force or torque. It is measured by the product of force and the perpendicular distance of the pivot from the line of action of force.
Examples of turning effect of force:
(i) Turning a steering wheel
(ii) Tightening a cap

Solution 35

A body is said to be in equilibrium under the action of a number of forces, if the forces are not able to produce any change in the state of rest or of uniform motion or uniform rotation.

Solution 36

Equilibrium in any case requires the ? forces acting on an object = 0, i.e. that there is
Fnet = 0.
Static equilibrium is the situation where the object upon which the forces act is no moving.
The object is "static" hence the state of equilibrium gets its name.
Dynamic equilibrium is the situation where an object is in constant velocity motion.
{This object can't experience an acceleration which means Fnet >0}

Solution 37

When the centre of gravity is nearer to the base of a body, the body is in stable equilibrium.
Conditions for stable equilibrium:
(a) The body should have a broad base.
(b) Centre of gravity of the body should be as low as possible.
(c) Vertical line drawn from the centre of gravity should fall within the base of the support.

Solution 38

(a) If both the forces act at the same point of the body, they have the same line of action, and then the moment becomes zero.
(b) If both the forces act at two different points of the body at a separation d then they constitute a torque whose value is given F x d.

Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 1 - Force, Work, Energy and Power Page/Excercise 73

Solution 39

Solution 40

(i) Pulling of a cart.
(ii) A ball falls down when it is dropped from a height

Solution 41

Solution 42

Solution 43

Solution 44

Solution 45

Solution 46

A body is said to be in equilibrium under the action of a number of forces, if the forces are not able to produce any change in the state of rest or of uniform motion or uniform rotation.
Conditions for stable equilibrium:
(a) The body should have a broad base.
(b) Centre of gravity of the body should be as low as possible.
(c) Vertical line drawn from the centre of gravity should fall within the base of the support.

Solution 47

Solution 48

Solution 49

(i) We keep our body balanced on two feet by keeping the center of gravity of our body between our feet. It acts normal to the sea level vertically downwards. If COG goes out we fall or we get unbalanced.
A boy standing on both legs has his COG in balanced position and is thus in stable equilibrium but a boy standing on one leg has his COG in unbalanced position which makes him quite unstable and hence it is easier to push him.
(ii) A man bends forward in order to keep himself in a stable equilibrium while climbing up a slope. By bending forward he increases the base of the support, so that the vertical line passing through his centre of gravity may still fall within the base.
(iii) When a truck is not fully loaded, its COG is at a high point and hence the turning moment of the weight is much greater, thus, the truck will be quite unstable and there are chances of toppling, when a truck takes a sharp turn.
(iv) When a man gets down from a moving train, his feet come to rest immediately, while the upper part of his body due to inertia of motion still remains in motion and consequently he leans in forward direction. The person while getting down of a train should run forward in the direction of the moving train to avoid fall.
(v) This is due to the fact that the body of the passenger is in the state of rest as long as the bus is at rest. When the bus starts, his feet acquire the velocity of the bus and come to motion with the moving bus, while the upper portion of his body due to inertia of rest tends to remain in the state of rest, resulting in his tendency to fall backwards.

Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 1 - Force, Work, Energy and Power Page/Excercise 74

Solution 50

To increase the stability of a body, its base should be made broad and heavy, and the centre of gravity of the body should be lowered.

Solution 51

(i) Two equal and opposite parallel forces acting along different lines on a body constitute a couple.(ii)

Solution 52

(i) Leaning tower of Pisa is stable because a line through the centre of gravity falls within the structure's base. If the line falls outside the structure's base then there is a possibility that overturning will occur. This structure could be classified as unstable.
(ii) We bend forward in order to keep ourselves in a stable equilibrium while climbing up a hill. By bending forward we increases the base of the support, so that the vertical line passing through our centre of gravity still falls within the base.
(iii) By keeping the legs apart, the base of the body broadens, thus the C.G. lowers and the body attains a more stable equilibrium.
(iv) Passengers are usually advised not to stand in the upper deck of the double deck bus. When the passengers are standing, the C.G. rises. This decreases the stability of the bus. When the passengers are sitting, the C.G. gets lowered and stability of the bus increases.

Solution 53

Solution 54

Solution 55

Solution 56

'Work' is said to be done when the applied force makes the body move i.e., there is a displacement of body.
It is equal to the product of force and the displacement of the point of application of the force in the direction of force.
The SI unit of work is 'joules' and the CGS unit is 'erg'.

Solution 57

(i) [C]
(ii) [A]
(iii) [D]
(iv) [E]
(v) [B]

Solution 58

Solution 59

Solution 60

Solution 61

The energy of a body is its capacity to do work.
The SI unit of work is 'joules' and the CGS unit is 'erg'.

Solution 62

When an elevator begins to move downwards in an accelerated mode, the forces acting on the body are the following:
a.Weight of the body acting downwards
b.Normal reaction of the floor acting upwards
c.The centrifugal force acting on the body, acting upwards.
Weight of the body is due to gravitational force on the body acting downwards.
Normal reaction is the force that is exerted by the elevator floor in response to the force with which the body presses itself against the floor.
The centrifugal force here  is fictious force that acts on the body in the direction opposite to the acceleration of the reference frame, here it is, the elevator floor. It is given by ma, where m is the mass of the body & a is the accelaration of the elevator floor. Centrifugal force is directed opposite to the acceleration of the elevator floor.
Weightlessness is the condition of the zero apparent weight.
When the acceleration of the elevator is such that the upward centrifugal force  Fc completely balances the downward weight Wt. of the body, the resultant normal reaction (N =Fc - Wt.) of the body is reduce dto zero. That's whene the body on the elevator floor will experience the state of weightlessness.

Solution 63

Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 1 - Force, Work, Energy and Power Page/Excercise 75

Solution 64

Solution 65

Solution 66

Solution 67

Solution 68

The energy of a body is its capacity to do work.
The SI unit of work is 'joules' and the CGS unit is 'erg'.
According to the law of conservation of energy, energy can neither be created nor be destroyed but can be transformed from one form to another. In other words, energy can be transformed from one form to another but the total amount of all the energies remain the same.

Solution 69

Six forms of energy:
1. Solar energy: The energy radiated by the sun is called the solar energy. Inside the sun, energy is produced by nuclear fusion reaction. Solar energy cannot be used to do work directly, because it is too diffused and is not always uniformly available. However, a number of devices such as solar panels, solar cells etc. have been invented to make use of solar energy.
2. Heat energy: The energy released on burning coal, oil, wood or gas is the heat energy. The stem possesses heat energy it has capacity to do work.
3. Light energy: It is the form of energy in presence of which other objects are seen. The natural source of light energy is sun. Many other sources of heat energy also give light energy.
4. Chemical or fuel energy: The energy possessed by fossil fuels such as coal, petroleum and natural gas is called chemical energy or fuel energy. These fuels are formed from the decayed remains of dead plants and animals that lived millions of years ago. In the interior of earth, due to high pressure and temperature the remains slowly changed into fossil fuels.
5. Hydro energy: The energy possessed by fast moving water is called the hydro energy. This energy is used to generate electricity in hydroelectric power stations. For this, dams are built across the rivers high up in the hills to store water. Water is allowed to run down the pipes and the energy of running water is used to turn a turbine. The turbine drives generators to produce electrical energy.
6. Nuclear energy: The energy released during the processes of nuclear fission and fusion is called nuclear (or atomic) energy. In both these processes, there is loss in mass which converts into energy in accordance with Einstein's mass-energy relation, E =mc2.

Solution 70

The energy possessed by a body by virtue of its position, shape or change of configuration is called potential energy.
Examples of potential energy:
(i) Water stored at a height in a reservoir.
(ii) A stretched spring.
(iii) A bent bow.
The energy possessed by a body by virtue of its motion is called kinetic energy.
Examples of kinetic energy:
(i) Air in motion has kinetic energy.
(ii) A swinging pendulum.
(iii) Moving hands of a clock.

Solution 71

Solution 72

Solution 73

(a) Potential energy
(b) Potential energy
(c) Kinetic energy
(d) Potential energy
(e) Kinetic energy

Solution 74


Solution 75

(e) P.E (Wound spring) to K.E. (motion)

Frank Modern Certificate Solution for Class 10 Physics Chapter Unit - 1 - Force, Work, Energy and Power Page/Excercise 76

Solution 76

(a) Electric bell
(b) Candle flame
(c) Dry cell
(d) Solar cell
(e) Electric iron

Solution 77

Solution 78

Solution 79

Solution 80

Solution 81

(a) Simple machine: A machine is a device by which we can either overcome a large resistive force at some point by applying a small force at a convenient point and in a desired direction or by which we can obtain a gain in speed.
(b) Lever: A lever is a rigid, straight or bent bar which is capable of turning about a fixed axis.
(c) Mechanical advantage (M.A.): The ratio of the load to the effort is called the mechanical advantage of the machine.
(d) Velocity ratio (V.R.): The ratio of the velocity of effort to the velocity of load is called the velocity ratio of the machine.
It is also defined as the ratio of the displacement of effort to the displacement of load.
(e) Efficiency: Efficiency of a machine is the ratio of the useful work done by the machine to the work put into the machine by the effort. In other words, it is the ratio of the work output to the work input.

Solution 82

E.g. of class I lever with M.A. = 1:  A physical balance has both arms equal (i.e. effort arm = load arm), thus its M.A. = 1
E.g. of class I lever with M.A. 1: A pair of scissors used to cut a piece of cloth has blades longer than the handle (i.e. effort arm is shorter than the load arm), thus its M.A. 1.
E.g. of class I lever with M.A. 1: Shears used for cutting thin metal sheets have much longer handles as compared to the blades (i.e. effort arm is longer than the load arm), thus its M.A. 1 and it serves as a force multiplier.

Solution 83

Solution 84

Or, E = 71.4 kgf

Solution 85

Solution 86

Solution 87

Frank Modern Certificate Physics - Part II Class 10 Chapter Solutions

TopperLearning provides step-by-step solutions for each question in each chapter in the Frank textbook recommended by ICSE schools. Access Chapter Unit - 1 - Force, Work, Energy and Power here. Our Frank Textbook Solutions for ICSE Class 10 Physics are designed by our subject matter experts. These solutions will help you to revise the whole chapter, so you can clear your fundamentals before the examination.

Text Book Solutions

ICSE X - Physics

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